Question

The area of a rectangle is 42 cm. If breadth of the rectangle is 6cm. What is the perimeter of rectangle?​

Answer 1

$\LARGE\sf{\texttt{{{Required Answer:}}}}$

Given ☆

• Area of the Rectangle = 42 cm

• Breadth of the Rectangle = 6 cm

To Find ☆

• The Perimeter of the Rectangle

Formula Used ☆

• Perimeter of Rectangle = 2 × ( Length + Breadth )

• Length of the Rectangle = Area ÷ Breadth

Solution ☆

To find the Perimeter of the Rectangle, first of all we need to find the Length of the Rectangle, and then using the Formula Perimeter of Rectangle = 2 × ( Length + Breadth ) we will find out the Perimeter of the Rectangle, so let's do it!

Length of the Rectangle = Area ÷ Breadth

Length of the Rectangle = 42 ÷ 6

Length of the Rectangle = 7 cm

Now, we have the Length of the Rectangle, let's find out the Perimeter of the Rectangle then!

Perimeter of Rectangle = 2 × ( Length + Breadth )

Perimeter of Rectangle = 2 × ( 7 + 6 )

Perimeter of the Rectangle = 2 × 13

Perimeter of the Rectangle = 26 cm

∴ Perimeter of the Rectangle is 26 cm

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$\LARGE\sf{\texttt{{{Important Formulas:}}}}$

Perimeter of Square = 4 × side

Perimeter of Rectangle = 2 × ( Length + Breadth )

Perimeter of Triangle = Sum of all sides

Area of Square = side × side

Area of Rectangle = Length × Breadth

Volume of Cube = side × side × side

Volume of Cuboid = Length × Breadth × Height

Note : We can also write the formula Area of Square = side × side as Area of Square = ( side )² and Volume of Cube = side × side × side as Volume of Cube = ( side )³

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Answer 2

Correct Question:

The area of a rectangle is 42 cm². If breadth of the rectangle is 6cm. What is the perimeter of rectangle?

To find:

• perimeter of rectangle

Given:

• Area of rectangle = 42 cm²

• breadth of rectangle = 6cm

Let :

• Length of rectangle = x

Solution:

We know:

$\big \checkmark \boxed{ \rm{perimeter \: of \: rectangle = 2(length + breadth)}}$

Now as we can see to find perimeter we should know value of length

So first let's find length:

We know

$\big \checkmark \boxed{ \rm{Area \: of \: rectangle =length\times breadth)}}$

Yep by using this formula we can find value of length of Rectangle

$\dashrightarrow\sf{}Area \: of \: rectangle =length\times breadth) \\ \\ \dashrightarrow \: \sf{}42=x\times 6 \\ \\ \dashrightarrow \sf{} \dfrac{42}{6} = x \\ \\ \dashrightarrow \sf x = \dfrac{42}{6} \\ \\ \dashrightarrow \sf x = \cancel \dfrac{42}{6} \\ \\ \dashrightarrow\underline{\boxed{ \sf{}x = 7}}$

.°. value of length of Rectangle = 7 cm

Bow let's find value of Perimeter my using formula as mentioned above

$\dashrightarrow \sf{}perimeter \: of \: rectangle = 2(length + breadth) \\ \\ \dashrightarrow \sf{}perimeter \: of \: rectangle =2( 7 + 6) \\ \\ \dashrightarrow \sf{}perimeter \: of \: rectangle =(2 \times 7) + (2 \times 6) \\ \\ \dashrightarrow \sf{}perimeter \: of \: rectangle =14 + (2 \times 6) \\ \\ \dashrightarrow \sf{}perimeter \: of \: rectangle =14 + 12 \\ \\ \dashrightarrow \underline{\boxed{\sf{}perimeter \: of \: rectangle =26 \: cm}}$

$\therefore$

$\underline{ \sf{}value \: of \: perimeter \: of \: reangle = 26cm}$

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Formulas related to SA & Volume :

$\begin{array}{|c|c|c|}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}$