Question

The area of a rectangle is 50cm^2 . The length is 5cm more than its breadth. What is the L and B of the rectangle?​

Answer 1

GIVEN:-

The area of the rectangle=50cm²

Length of the rectangle is 5 cm more than the breadth

TO FIND:-

Length and breadth of the rectangle

EXPLANATION:-

For a rectangle

let breadth be x

then according to the question

length=(x+5)cm

And given

AREA OF THE RECTANGLE=50cm²

we know that

$\boxed{\bf Area \: of \: rectangle =lb \: square\: units}$

Now substituting the values

$= > x(x + 5) = 50 \\ = > {x}^{2} + 5x - 50 = 0 \\ = > {x}^{2} + 10x - 5x - 50 = 0 \\ = > x(x + 10) - 5( x+ 10) = 0 \\ = > (x + 10)(x - 5) = 0$

Equating separately

$x + 10 = 0 \\ = > \boxed{ \sf \: x = - 10cm}$

$x - 5 = 0 \\ = > \boxed{ \sf \: x = 5cm}$

but we know that breadth cannot be in negative so,x=-10 is negligible

$\underline{\bf breadth=x=5cm}$

$\underline{\bf length=(x+5)=10cm}$

Answer 2

Step-by-step explanation:

x^2+5x=50

x^2+5x-50=0

x^2+10x-5x-50=0

x(x+10)-5(x+10)

x=5 or x=-10

as length can't be negative

x=5

so length is 10 and breadth is 5