Question

the area of a rectangle is 540 CM square if its length is 27 cm find its width and perimeter

Answer 1

breadth = 540÷27 =20cm. perimeter =2 (27+20)=94cm

Answer 2

Let width of rectangle be x cm
Given that
Area= 540sq cm
Length = 27 cm
According to problem
Area of rectngle = length X breadth (width)
So 27 ( x)=540
x= 540/27
x = 20
There fore width =20cm
Perimeter of rectangle = 2(l+b)
= 2(27+20)
=2(47)
= 94 sq cm
There fore perimeter = 94sq cm