Question

the area of a rectangle is 540 cm2 and its length is 36 CM. find its width and perimeter.
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Answer 1

Answer:

540=lb

540=36b

b=540/36

b=15

P=2(l+b)

=2(36+15)

=2(51)

=102cm

Answer 2

✬ Breadth = 15 cm ✬

✬ Perimeter = 102 cm ✬

GIVEN:

• Area of rectangle = 540 cm ²
• Length of the rectangle = 36 cm

TO FIND:

• What is the Breadth and Perimeter of the rectangle = ?

SOLUTION:

Let the Breadth of the rectangle be 'B' cm

We know that, the formula for finding the Area of rectangle is :-

✫ Area of rectangle = L$\times$B ✫

According to question:-

$\implies$ 36 $\times$ B = 540

$\implies$ B = 540/36

$\implies$ B = 15 cm

❛ Hence, the breadth of the rectangle is 15 cm ❜ 

Now, we have to find the Perimeter of the rectangle

We know that the formula for finding the perimeter of rectangle is:-

⠀✫ 2(Length + Breadth) ✫

$\implies$ Perimeter = 2(36 + 15) cm

$\implies$ Perimeter = 2 $\times$ 51cm

$\implies$ Perimeter = 102 cm

❛ Hence, the Perimeter of the rectangle is 102 cm ❜

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✯ Extra Information ✯

➩  All angles of a rectangle are 90°.

➩  Diagonals of a rectangle bisect each other.

➩  Opposite sides of a rectangle are equal.

➩  Diagonals of a rectangle are equal in Length.