Question

The area of a rectangle is 540 cm2 and its length is 36 cm. Find its width and perimeter

Answer 1

The width of a rectangle(b) = 15 cm and the perimeter of a rectangle = 102 cm

Step-by-step explanation:

Given,

The area of a rectangle = 540 cm^2cm

2

and

the length of a rectangle(l) = 36 cm

To find, the width of a rectangle(b) and perimeter = ?

We know that,

The area of a rectangle = l × b

⇒ 36 × b = 540

⇒ b=\dfrac{540}{36}=15cmb=

36

540

=15cm

∴ The width of a rectangle(b) = 15 cm

The perimeter of a rectangle = 2(l + b)

= 2 × (36 cm+ 15 cm)

= 2 × 51 cm

= 102 cm

Hence, the width of a rectangle(b) = 15 cm.

and the perimeter of a rectangle = 102 cm

l hope this answer is useful for you

please give me a brianlist

thanks for regarding

Brianly teacher