The area of a rectangle is 540 cm2 and its length is 36 cm. Find its width and perimeter
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The width of a rectangle(b) = 15 cm and the perimeter of a rectangle = 102 cm
Step-by-step explanation:
Given,
The area of a rectangle = 540 cm^2cm
2
and
the length of a rectangle(l) = 36 cm
To find, the width of a rectangle(b) and perimeter = ?
We know that,
The area of a rectangle = l × b
⇒ 36 × b = 540
⇒ b=\dfrac{540}{36}=15cmb=
36
540
=15cm
∴ The width of a rectangle(b) = 15 cm
The perimeter of a rectangle = 2(l + b)
= 2 × (36 cm+ 15 cm)
= 2 × 51 cm
= 102 cm
Hence, the width of a rectangle(b) = 15 cm.
and the perimeter of a rectangle = 102 cm
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