the area of a rectangle is 540sq.cm & its length is 36 cm. find ots width and perimeter..solve it plz by class 6 method
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area of rectangle = 540 cm²
= length × breadth = 540 cm²
= 36×breadth = 540 cm²
= breadth = 540/36 = 15 cm
since , length = 36 cm and breadth = 15 cm
we have , perimeter = 2(length + breadth)
= perimeter of rectangle = 2(36+15) cm
= perimeter of rectangle = (2×51) cm
= perimeter of rectangle= 102 cm
hope this helps
= length × breadth = 540 cm²
= 36×breadth = 540 cm²
= breadth = 540/36 = 15 cm
since , length = 36 cm and breadth = 15 cm
we have , perimeter = 2(length + breadth)
= perimeter of rectangle = 2(36+15) cm
= perimeter of rectangle = (2×51) cm
= perimeter of rectangle= 102 cm
hope this helps
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