Question

The area of a rectangle is 54m^2 and its length is 3m more than widht . Find its dimensions​

Answer 1

width be x units and length be (x + 3) units

Area = 54

Length×breadth = 54

x(x + 3) = 54

x² + 3x = 54

x² + 3x - 54 = 0

x² + (9 - 6)x - 54 = 0

x² + 9x - 6x - 54 = 0

x(x + 9) - 6(x + 9) = 0

(x + 9)(x - 6) = 0

x= -9 or x = 6

Taking positive value, x= 6

then,

breadth = x => 6

Length = x + 3 = 6 + 3 = 9

I hope this will help you

Answer 2

Let length = 2x + 3

Let width = x

Area = 54 ft2

length × width = Area

x(2x + 3) = 54

2x2 + 3x = 54

2x2 + 3x - 54 = 0

(2x - 9)(x + 6) = 0

x = 9/2 and x = -6

x = 4.5 and x = -6

We accept x = 4.5 because length cannot be a negative value. Substituting this value into the dimensions:

width = 4.5 ft

length = 2(4.5) + 3 = 9 + 3 = 12 ft