Question

the area of a rectangle is 60 sq. cm and its diagonal is 13 cm, find its perimeter.​

Answer 1

Answer:

let length of rectangle is x and breadth of rectangle is y

then from property of rectangle

x^2+y^2=13^2=169 ----------(1)

now again ask

xy=60 cm^2

2xy=120 ----------(2)

add equation (1) and (2)

(x+y)^2=(17)^2=+_17

but here consider only positive part

x+y=17 --------(3)

now subtract equation (1) to (2)

(x-y)^2=(7)^2

x-y=+_7

hence x-y=7-------------(4)

now solve equation (3) and (4)

x=12cm and y=5cm

and perimeter of rectangle=2 (12+5)=34cm

Step-by-step explanation:

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