the area of a rectangle is 650cm2 and its width is 13cm. find the perimeter of the rectangle. also, calculate its area if the length of the rectangle is 15% more than its width
Answers
Answered by
6
given width (b) = 13 cm
area of rectangle = 650 cm ^2
length × width = 650 cm^2
length × 13 = 650
length = 50 cm
perimeter of rectangle
=2 (length+width )
=2(50 + 13 )= 2 × 63 =126 cm
given , calculate area if length is 15% more than its width
given breadth = 13 cm
so now length will be = 13 + 15% of 13
= 13 + 1.95
=14.95 cm
new area = breadth × new length
= 13 × 14.95 = 194.35 cm^2
therefore,
area of rectangle=194.35cm^2
_______________________________
Your answer: p=126cm , A=194.35 cm^2
_______________________________
area of rectangle = 650 cm ^2
length × width = 650 cm^2
length × 13 = 650
length = 50 cm
perimeter of rectangle
=2 (length+width )
=2(50 + 13 )= 2 × 63 =126 cm
given , calculate area if length is 15% more than its width
given breadth = 13 cm
so now length will be = 13 + 15% of 13
= 13 + 1.95
=14.95 cm
new area = breadth × new length
= 13 × 14.95 = 194.35 cm^2
therefore,
area of rectangle=194.35cm^2
_______________________________
Your answer: p=126cm , A=194.35 cm^2
_______________________________
genius2213:
thank u sooooo much
Similar questions