Question

The area of a rectangle is 672 sq m and one side is 16 m . find perimeter of the rectanlge

Answer 1

heya!! mate^_^

your answer is - - - -

Given :-

area of rectangle=672sq.m

one side measures=16m

area=length × breadth

$672=x×16$

$x=672/16$

$x=42m$

so,

$length=42m$

$breadth=16m$

perimeter of rectangle=

$2 (l+b)$

$=2(42+16)$

$=2 (58)$

$=116m^2$

Answer 2

Length= area of rectangle ÷ one side of the rectangle =672÷ 16 =42 , length =42 perimeter =2×(42+16)=58 2×58= 116 , perimeter =116