Math, asked by roblox0842, 19 days ago

The area of a rectangle is 6x2+17xy+12y2 square unit and its length is3x+4y unit.Find its breadth.

Answers

Answered by akshatmantri21
0

Answer:

Step-by-step explanation:

It is given that

Area of a rectangle  6x  

2

−4xy−10y  

2

 square unit

Length = 2x+2y unit

We know that

Breadth = Area / Length

So we get

=(6x  

2

−4xy−10y  

2

)/(2x+2y)

3x−5y units

Answered by Hansika4871
0

Given:

The area of a rectangle is 6x² + 17xy + 12y². The length of the rectangle is 3x + 4y.

To Find:

The breadth of the rectangle.

Solution:

The given problem can be solved using the concepts of factorization.

1. The area of the rectangle of length l and breadth b is,

=> Area of the rectangle = Length x Breadth,

=> Area of the rectangle = l x b.  

2. Substitute the data in the given formula,

=>  6x² + 17xy + 12y² = 3x + 4y x breadth.

3. The area of the rectangle can be factorized as.

=> 6x² + 17xy + 12y²,

=> 6x² + 9xy + 8xy + 12y²,

=> 3x(2x + 3y) + 4y(2x + 3y),

=> (2x + 3y)(3x+4y).

4. Area of the rectangle = (2x + 3y)(3x+4y) = 3x + 4y x breadth,

=> After cancelling the like terms,

=> breadth = 2x + 3.

Therefore, the breadth of the rectangle is 2x + 3.

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