The area of a rectangle is 6x2+17xy+12y2 square unit and its length is3x+4y unit.Find its breadth.
Answers
Answer:
Step-by-step explanation:
It is given that
Area of a rectangle 6x
2
−4xy−10y
2
square unit
Length = 2x+2y unit
We know that
Breadth = Area / Length
So we get
=(6x
2
−4xy−10y
2
)/(2x+2y)
3x−5y units
Given:
The area of a rectangle is 6x² + 17xy + 12y². The length of the rectangle is 3x + 4y.
To Find:
The breadth of the rectangle.
Solution:
The given problem can be solved using the concepts of factorization.
1. The area of the rectangle of length l and breadth b is,
=> Area of the rectangle = Length x Breadth,
=> Area of the rectangle = l x b.
2. Substitute the data in the given formula,
=> 6x² + 17xy + 12y² = 3x + 4y x breadth.
3. The area of the rectangle can be factorized as.
=> 6x² + 17xy + 12y²,
=> 6x² + 9xy + 8xy + 12y²,
=> 3x(2x + 3y) + 4y(2x + 3y),
=> (2x + 3y)(3x+4y).
4. Area of the rectangle = (2x + 3y)(3x+4y) = 3x + 4y x breadth,
=> After cancelling the like terms,
=> breadth = 2x + 3.
Therefore, the breadth of the rectangle is 2x + 3.