Question

The area of a rectangle is 6x² - 4xy - 10y² square unit and length is 2x + 2y unit. Find its breadth.​

Answer 1

Step-by-step explanation:

Area of a rectangle

= 6x2 – 4xy – 10y2 sq. units

Length = 2x + 2y units

∴ Breadth = Area/Length

= (6x2 – 4xy – 10y2)/(2x + 2y)

= 3x + 5y units

Hence, breadth = 3x – 5y units

Answer 2

Given :-

• Area of rectangle = 6x²-4xy-10y²

• Length of rectangle = 2x+2y

To Find :-

• Breadth of the rectangle

Formulae Used :-

$\large\pink{ \sf{area \: of \: rectangle = length \times breadth}}$

Solution :-

$\ \: { \sf{area \: of \: rectangle = (2x + 2y)(breadth)}} \\ \\ \ \: { \sf{breadth \: = \frac{6 {x}^{2} - 4xy - 10 {y}^{2} }{2x + 2y} }} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \ \: { \sf{breadth = \frac{(2x + 2y)(3x - 5y)}{2x + 2y} }} \: \: \: \: \: \: \: \: \: \: \: \\ \\ \huge\fbox\red { \sf{breadth \: = \: 3x - 5y}}$