the area of a rectangle is(6x²(x-15)sq. unit and one of it sides are (3x+5)unit find the length of the adjacent side
Answers
Answer:
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Step-by-step explanation:
Area of rectangle
Width
In area equation, multiply coefficient of first term with third term, which is constant and find factors.
Now check for middle term and try to find out whether addition or subtraction of factors equals to coefficient of middle term or not?
Yes this equation can be factored.
First bracket is divisible by and second is divisible by , so simplify it.
One of the factors of this equation is equal to width of rectangle, so division results into,
and that's the length of rectangle.The area of a rectangle is 6x^2 + 5x – 6, and its width is 3x – 2. What is the length of the rectangle?
Area of rectangle = 6x2+5x−6
Width = 3x−2
In area equation, multiply coefficient of first term with third term, which is constant and find factors.
6×(−6)=−36 ⟹ −1×2×2×3×3=−36
Now check for middle term and try to find out whether addition or subtraction of factors equals to coefficient of middle term or not?
(3×3)+(−1×2×2)=9−4=5 ✓
Yes this equation can be factored.
(6x+9)(6x−4)
First bracket is divisible by 3 and second is divisible by 2 , so simplify it.
(2x+3)(3x−2)
One of the factors (3x−2) of this equation is equal to width of rectangle, so division results into,
(2x+3) and that's the length of rectangle.