Question

The area of a rectangle is 6xsquarey +4ysquarex and the width is 2xy. What is the perimeter of the rectangle

Answer 1

Answer:

Area of a rectangle = l * b

6x^2 + 4y^2x = l * 2xy

2xy(3x+2y). = l * 2xy

3x+2y = l

Length = 3x + 2y

Breadth .=. 2xy

Perimeter of a rectangle = 2(l + b)

= 2(3x + 2y + 2xy)

= 6x + 4y + 4xy