Math, asked by nathanbouned3314, 11 months ago

The area of a rectangle is 70 in² and the length of the rectangle is 3 in. longer than the width.


The area of a rectangle is found by multiplying the length times the width.


During the Set Up step of the five-step problem-solving plan, which equation would you set up to solve for the width?



a) w + 3w = 70
b) w(w+3)=70
c) 3w = 70
d) w + 3 = 70

Answers

Answered by Blaezii
2

Answer:

w+3 = 70 (option d)

Step-by-step explanation:

Given Problem:

The area of a rectangle is 70 in² and the length of the rectangle is 3 in. longer than the width.

The area of a rectangle is found by multiplying the length times the width.

During the Set Up step of the five-step problem-solving plan, which equation would you set up to solve for the width?

a) w + 3w = 70

b) w(w+3)=70

c) 3w = 70

d) w + 3 = 70

Solution:

Rectangle Formula:

W.L = rectangle area

W.(w+3) = 70

Hence,

Answer is (Option D)

Answered by qweenemily
2

Answer:

B w(w+3)=70

Step-by-step explanation:

i took the test on k12 and this was the answer

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