Question

the Area of a rectangle is (a⁴-2a³-7a²+ 8a+12) sq. units. One of its sides measure (a²-a-6) units. find perimeter​​

Answer 1

Answer:

4a^2 - 4a - 16

Step-by-step explanation:

The area of the rectangle = a^4 - 2a^3 - 7a^2 + 8a + 12

One side = a^2 - a - 6

We know that , if we divide one side with the area, we get the length of the other side.

Upon dividing the area by the side given , we get the result : a^2 - a - 2

Formula for finding the perimeter of a rectangle = 2(l+b)

=> 2(a^2 - a - 6 + a^2 - a - 2)

= 2(2a^2 - 2a - 8)

= 4a^2 - 4a - 16. [Using distributive property]

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