Math, asked by ILiveForMemesP, 4 months ago

The area of a rectangle is p² - 13p -30. Find its length and breadth. ​

Answers

Answered by gyanwanibhavesh897
1

Factorise the following

p {}^{2}  - 13p -  30

p {}^{2} -15p + 2p - 30

P(P-15)+2(P-15)

(P-15)(P+2) are the length and breadth of Rectangle

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Answered by hukam0685
0

\bf (p + 2) \: and \: (p - 15) are length and breadth of rectangle respectively.

Step-by-step explanation:

Given:

  • The area of rectangle is  {p}^{2}  - 13p - 30.

To find:

  • Find length and breadth of rectangle.

Solution:

Concept to be used:

  • Factorize the quadratic polynomial.
  • Two factors are length and breadth of rectangle.

Step 1:

Factorize the quadratic polynomial.

 {p}^{2}  - 13p - 30 \\

or

split the middle term.

 {p}^{2}  - 15p + 2p - 30 \\

or

 = p(p - 15) + 2(p - 15) \\

or

\bf {p}^{2} - 13p - 30 = (p + 2)(p - 15) \\

Step 2:

Find length and breadth.

As factors of polynomial are (p + 2)(p - 15) \\

Normally, we are taking longer side as length and shorter as breadth.

So,

Length of rectangle is (p + 2) unit.

Breadth of rectangle is (p - 15) unit.

Thus,

\bf (p + 2) \: and \: (p - 15) are length and breadth of rectangle respectively.

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