Question

The area of a rectangle is (x² + 3x -10) square units . if its length is (x-2)units then the breadth is ?​

Answer 1

Answer:

b (breadth = 3x - 10)

Step-by-step explanation:

area of rectangle = length × breadth

x2 + 3x -10= x-2 × b

x2 + 3x - 10= x2 × b

x2 - x2 + 3x -10 = b

3x - 10 = b

Answer 2

$\large\sf\underline{↬Question}$

The area of a rectangle is (x² + 3x -10) square units . if its length is (x-2)units then the breadth is ?

$\large\fbox\red{Answer}$

$\sf\:✰\:Given\:$

• $\sf\:Area\:of\:rectangle\:=x^{2}+3x-10\:sq.units$

• $\sf\:length\:=x-2\:units$

$\sf\:✰\:Solution\:$

We know,

$\boxed{\red{Area\: of\:rectangle\:= l\times b}}$

Applying this :

$\sf\:Area\:of\:rectangle\:=x^{2}+3x-10\:$

$\sf\:➪ \:l \times b = x^{2}+3x-10\:$

$\sf\: ➪ \:(x-2) \times b = x^{2}+3x-10\:$

$\sf\:➪ \:(x-2) \times b = x^{2} + (5-2)x-10\:$

$\sf\:➪\:(x-2)\times b = x^{2}+5x-2x-10\:$

$\sf\:➪\:(x-2) \times b=x(x+5) -2(x+5) \:$

$\sf\:➪\:(x-2) \times b=(x+5) (x-2) \:$

$\sf\:➪\:b=\frac{(x+5) (x-2) }{(x-2) }\:$

$\sf\:➪\:b=(x+5) \:units\:$

☑ So breadth = ( x + 5 ) units.

Thnku ❣