The area of a rectangle
whose breadth is 9cm and
perimeter is 50 cm
plz guys urgent
Answers
Answered by
1
Answer:
a of rectang: l×b
" " " =50×9
=450cm square.
Answered by
1
Answer:
let the length be = x cm
then perimeter = 2(length + breadth)
given perimeter = 50 cm
50 = 2(x+9)
50=2x+18
2x=50-18
2x=32
x=32/2
x=16
hence length = 16 cm and breadth = 9cm
area = length* breadth
area = 16*9
=144 cm^2
Similar questions