Math, asked by itz1234karmathekille, 5 months ago

The area of a rectangle whose length and breadth are (x + 3) and (x + 7) respectively is
(a) x² + 10x +21
(b) x² + 21x + 10
(c) 3x² + 7x + 21
None of these​

Answers

Answered by WhistlingCold
2

Answer:

(a) x square + 10x + 21

Step-by-step explanation:

Please mark as brainiest

x+3 ( x+7)

x square + 7x + 3x + 21 = x square + 10x + 21

Answered by Anonymous
3

GivEn:

  • Length of rectangle = x+3
  • Breadth of rectangle = x+7

To finD:

  • Area of rectangle.

Solution:

We have given that length and breadth of recrangle is x+3 and x+7 respectively.

Formula using:

Area of rectangle = Length× Breadth.

Where:

  • Length = x+3 ••••(given)
  • Breadth = x+7 ••••( given)

Putting values in formula:

Area of rectangle = Length × Breadth

→ Area of rectangle = (x+3) × (x+7)

→ Area of rectangle = x(x+7) +3(x+7)

→ Area of rectangle = x²+7x+3x+21

→ Area of rectangle = x²+10x +21

Our answer:-

\small{\tt{\green{ Area \: of \: rectangle\: =\: x²+10x+21 \:i.e\: option\: A ✓ }}}

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