Math, asked by 20012m210, 1 month ago

The area of a rectangle whose length is twice its breadth is increasing at the rate of 8 cm-/sec. Find the rate at which length is increasing when the breadth is 5 cm. ​

Answers

Answered by tanishqkadyan
1

Answer:

Let length =x

breadth =y

Area of rectangle =xy

A=x

x

=x

3

/2

dt

dA

=48cm

2

/sec

dt

dA

=

2

3

x

dt

dx

x=4.5cm

48=

2

3

×

4.5

×

dt

dx

4.5

32

=

dt

dx

⇒15.08

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