Question

the area of a rectangle whose sides are 2a²b and 3a²b² is​

Answer 1

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Given :-

Sides of a triangle are 2a²b and 3a²b²

To find :-

Area of triangle

Solution :-

Let length be 2a²b

and breadth be 3a²b²

We know

Area of rectangle = length×breadth

Area of rectangle = 2a²b×3a²b²

Area of rectangle = 6a⁴b³sq.units