Question

The area of a rectangular carpet is 120 m^2 and it's perimeter is 46 m . The length of its diagonal is​

Answer 1

Answer:

Area of the rectangular carper =120 cm  

2

 

Perimeter =46 m

2(l+b)=46

(l+b)=46/2

l+b=23

And, length × breadth=120

Now, we know that :

(l−b)  

2

=(l+b)  

2

−4lb

(l−b)  

2

=(23)  

2

−4×120

(l−b)  

2

=529−480

(l−b)  

2

=49

(l−b)  

2

=(7)  

2

 

Hence, l−b=7

And l+b=23

By adding, we get 2l=30

l=30/2

l=15

and, b=23−15

b=8

Diagonal =  

(l  

2

+b  

2

)

​  

 

=  

(15)  

2

+(8)  

2

 

​  

 

=  

(225+64)

​  

 

=  

(289)

​  

 

=17 m