The area of a rectangular carpet is 120 m square and its perimeter is 46 metre the length of its diagonal is
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Area of rectangle l×b=120m^2_--------1)
【where l=lenght and b=breadth 】
and ,perimeter if rectangle =2(l+b)=46
=)l+b=23-------2)
=) l-b=√(l+b)^2-4lb.
=)l-b=√529-4×120 【from 1 ) and 2)】
=)l-b=√529-480
=)l-b=√49
=)l-b=7______3)
now,adding 1)and 3 )
we get,
l+b=23
l-b=7
----------
2l=30
l=15.
and again putting on 1)
b=8 ..
now for finding the diagonal we use Pythagoras theorm..
d=√15^2+64
d=17m
hoping it helps
thanks
Area of rectangle l×b=120m^2_--------1)
【where l=lenght and b=breadth 】
and ,perimeter if rectangle =2(l+b)=46
=)l+b=23-------2)
=) l-b=√(l+b)^2-4lb.
=)l-b=√529-4×120 【from 1 ) and 2)】
=)l-b=√529-480
=)l-b=√49
=)l-b=7______3)
now,adding 1)and 3 )
we get,
l+b=23
l-b=7
----------
2l=30
l=15.
and again putting on 1)
b=8 ..
now for finding the diagonal we use Pythagoras theorm..
d=√15^2+64
d=17m
hoping it helps
thanks
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