Question

the area of a rectangular carpet is 120m square and its perimeter is 46m . the length of its diagonal is?

Answer 1

heya ☺

Area of rectangle l×b=120m^2_--------1)

【where l=lenght and b=breadth 】

and ,perimeter if rectangle =2(l+b)=46

=)l+b=23-------2)

=) l-b=√(l+b)^2-4lb.

=)l-b=√529-4×120 【from 1 ) and 2)】

=)l-b=√529-480

=)l-b=√49

=)l-b=7______3)

now,adding 1)and 3 )

we get,

l+b=23
l-b=7
----------
2l=30

l=15.
and again putting on 1)

b=8 ..
now for finding the diagonal we use Pythagoras theorm..

d=√15^2+64
d=17m.

hope it help you.


@rajukumar☺☺☺☺

Answer 2

Given that perimeter of a rectangular carpet = 46m.

      2(l + b) = 46

          l + b = 23   ---------- (1)


Given that Area of a rectangular carpet = 120m^2.

          l * b = 120   ------------ (2)


We know that length of the diagonal 

root l^2 + b^2

= root (l + b)^2 - 2lb

= root(23)^2 - 2 * 120

= root 529 - 240

= root 289

= 17.


Therefore the length of the diagonal = 17m.


Hope this helps!