Math, asked by tushargarg953, 4 months ago

the area of a rectangular field is 0.5 hectares. if one of the sides of the field is 40 metre ,find the other side.​

Answers

Answered by farhaanaarif84
0

Answer:

Given that diagonal of a rectangular field is 60 metres more than the shorter side

So diagonal will = x+60m

Given that the longer side is 30 metres more than the shorter side =Longer side = x+30m

All angles in rectangle is always = 90

so that we can Use Pythagoras theorem

Diagonal

2

= shorterside

2

+longerside

2

Plug the values In this we get (x+60)

2

= (x)

2

+ (x+30)

2

= x

2

+x

2

+60x+900

(a+b)

2

=a

2

+b

2

+2ab

We get x

2

+120x+3600 = x

2

+x

2

+60x+900

x

2

+120x+3600 subtracting both side we get

0=x

2

−60x−2700

Factorize it now x

2

−90x+30x−2700=0

x(x−90)+30(x−90)=0

(x−90)(x+30)=0

x−90=0orx+30=0

x=90 or x=−30

Any side of rectangle cannot negative

so shorter side = x+30=90+30=120 m

Diagonal is = x+60=90+60=150 m

10000 = 5000 m^2 so, area=l. B= l. 12=5000, l=5000/12.5=400m so other side is 400m.

Answered by kumar3590
2

Answer:

125m

Step-by-step explanation:

let, other side=x

0.5hectare =5000m²

therefore,

5000=x × 40

x=125 m

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