Question

the area of a rectangular field is 120 square metre if the length is 15 M find the breadth and the perimeter of the rectangle​

Answer 1

Answer:

we have

area of rectangle =length *bredth

therefore 120 = 15 * bredth

bredth =120\15

bredth=8

Step-by-step explanation:

Answer 2

$\bf{\underline{\underline \blue{Solution:-}}}$

$\sf\underline{\red{\:\:\: AnswEr:-\:\:\:}}$

• The breadth of the rectangular filed = 8m
• The Perimeter of the rectangular field = 46 m

$\sf\underline{\red{\:\:\: Given:-\:\:\:}}$

• The area of a rectangular field is 120 square metre.
• The length of the rectangular field is 15 metre.

$\sf\underline{\red{\:\:\: Need\:To\:Find:-\:\:\:}}$

• The breadth of the rectangular filed = ?
• The Perimeter of the rectangular field = ?

$\bf{\underline{\underline \blue{Explanation:-}}}$

$\dag$ In First Situation:

$\sf\underline{\green{\:\:\: Need\:To\:Find:-\:\:\:}}$

• The breadth of the rectangular filed = ?

$\sf\underline{\red{\:\:\: Formula\:used\:here:-\:\:\:}}$

$\bigstar \: \boxed{ \sf \: Area\:of\: rectangle = Length \times Breadth}$

$\sf\underline{\pink{\:\:\: Now,Putting\:the\: values:-\:\:\:}}$

$\dashrightarrow \sf {120 = 15 \times Breadth}$

$\dashrightarrow \sf {\dfrac{\cancel{120}}{\cancel{15}} = Breadth }$

$\dashrightarrow \sf {Breadth = 8\:m}$

$\sf\underline{\red{\:\:\: ThereFore:-\:\:\:}}$

• The breadth of the rectangular filed is 8m.

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$

$\dag$ In Second Situation:

$\sf\underline{\green{\:\:\: Need\:To\:Find:-\:\:\:}}$

• The Perimeter of the rectangular field = ?

$\sf\underline{\red{\:\:\: Again,\: Formula\:Used\:Here:-\:\:\:}}$

$\bigstar \: \boxed{ \sf \: Perimeter\:of\: rectangle = 2 \times (Length + Breadth) }$

$\sf\underline{\pink{\:\:\: Now,Putting\:the\: values:-\:\:\:}}$

$\dashrightarrow \sf {Perimeter\:of\: rectangle = 2 \times (15 + 8) }$

$\dashrightarrow \sf {Perimeter\:of\: rectangle = 2 \times 23}$

$\dashrightarrow \sf {Perimeter\:of\: rectangle = 46\:m }$

$\sf\underline{\red{\:\:\: ThereFore:-\:\:\:}}$

• The perimeter of the rectangular filed is 46 m.

$\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}$