Math, asked by keicruz2118, 11 months ago

The area of a rectangular field is 160m^2 and its length is twice its width. Find the dimensions of the field.

Answers

Answered by raji8115
8

l = 2b

lb = 160

2b² = 160

b = 2√10 m = 6.32 m (approx)

Answered by Steph0303
18

Answer:

Length = 8√5 m, Breadth  = 4√5 m

Step-by-step explanation:

Area of the rectangular field = 160 m²

Area of rectangle = l × b

According to the question,

Length ( l ) = 2 × Breadth ( b )

Therefore interpreting the question we get,

⇒ l × b = 160 m²

⇒ 2b × b = 160 m²   [ Since l = 2b ]

⇒ 2b² = 160 m²

⇒ b² = 160 / 2 = 80 m²

⇒ b = √80 = 4√5 m

Therefore Length = 2 × b

⇒ l = 2 × 4√5 m

⇒ l = 8√5 m

Therefore the dimensions of the field are:

  • Length = 8√5 m
  • Breadth = 4√5 m
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