Question

the area of a rectangular field is 48 m square and one of its side is 6 metre how long will a lady take to cross the field diagonally at the rate of20 m per minute​

Answer 1

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$<b>$]
l×b=48

Let,

length be 6

then,

6×b=48

b=8

By Pythagoras therorem

H^2=P^2+B^2

=(6)^2+(8)^2

=36+64

H^2=100

H=10m

At the rate of 20=200

Answer 2

Answer:   30 secs.   

Step-by-step explanation:  Let ABCD be the rectangular field of area 48 metre square and let AB=CD=6 metre. So, BC=AD= 48/6=8 metre.

The lady is crossing the field diagonally, so she is walking along BD. Also, since every angle of a rectangle is 90°, so ΔABD is a right angled-triangle with BD as the hypotenuse.

Therefore, using Pythagoras theorem, we have

Now, to cover 20 metre, the lady takes 1 min.

So, to cover 10 metre, the lady will take min=30 secs.

Thereforere, the lady will take 30 seconds to cross the field diagonally.