Question

The area of a rectangular field is 520 Sq my and one of its sides is 13m find the perimeter of the rectangle

Answer 1

Answer:40 ; 106

Step-by-step explanation:

L×B = area = 520

13×B=520

B=40cm

Perimeter = 2(L+B)

=2(40+13)

=2(53)

=106cm

Answer 2

Area of rectangle = l×b = 520
so,
$520 = x \times 13 \\ \frac{520}{13} = x \\ x = 40$
so, one side is 40m
Therefore perimeter of rectangle = 2(l+b)
$2(40 + 13) = 2(53) \\ = 106m$
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