Question

the area of a rectangular field is (. a sq - 19a + 90) square units. Find the width of the rectangle if its length is ( a - 9) units.​

Answer 1

Answer:

a²-19a+90

=(lcm of 90= 5×3×3×2=10 × 9)

a²-10a-9a+90

=a(a-10)-9(a-10)

=(a-9)(a-10)

THEREFORE, if (a-9) is the length then (a-10) is the breadth.

PLEASE MARK AS BRAINLIEST..... AND FOLLOW PLS....

Answer 2

Step-by-step explanation:

Heya mate;

solution..

Given,

area of rectangular field= (a^-19a+90)

length=(a-9).

(a^-19a+90) after Factorising this,

(a^-10a-9a+90)

[a(a-10) - 9(a-10)]

(a-9) (a-10)

If Length=(a-9)

Hence Width= (a-10)

Thanks....