Question

The area of a rectangular Field is$786 mx^{2}$ and its length is 32m .Find:
(i)the breadth of the field
(ii)the cost of fencing it at ₹20 per metre

Answer 1

Answer :

• breadth of the field is 24m
• cost of fencing is ₹2400

Given :

• Area of a rectangular field is 786m²
• Length is 32m

To find :

• The breadth of the field
• The cost of fencing it at ₹20 per metre

Solution:

(1) The breadth of the field :

As we know that,

• Area of rectangle = l x b

where l is 32m , Area of rectangle is 786m² and breadth is ?

⟿ Area of rectangle = l × b

⟿ 786m² = 32 × b

⟿ b = 786/32

⟿ b = 24m

∴ breadth is 24m .

Now perimeter of the field:

• perimeter of rectangle = 2(l + b)

where length is 32m , breadth is 24m

⟿ 2 (length + breadth)

⟿ 2(32 + 24)m²

⟿ 2(56) m²

⟿ 112m²

∴ perimeter of field is 112m² .

(2) The cost of fencing at ₹20 per meter :

⟿ 20 × 112

⟿ 2240

∴ cost of fencing is ₹ 2240

Answer 2

Answer:

Answer :

breadth of the field is 24m

cost of fencing is ₹2400

Given :

Area of a rectangular field is 786m²

Length is 32m

To find :

The breadth of the field

The cost of fencing it at ₹20 per metre

Solution:

(1) The breadth of the field :

As we know that,

Area of rectangle = l x b

where l is 32m , Area of rectangle is 786m² and breadth is ?

⟿ Area of rectangle = l × b

⟿ 786m² = 32 × b

⟿ b = 786/32

⟿ b = 24m

∴ breadth is 24m .

Now perimeter of the field:

perimeter of rectangle = 2(l + b)

where length is 32m , breadth is 24m

⟿ 2 (length + breadth)

⟿ 2(32 + 24)m²

⟿ 2(56) m²

⟿ 112m²

∴ perimeter of field is 112m² .

(2) The cost of fencing at ₹20 per meter :

⟿ 20 × 112

⟿ 2240

∴ cost of fencing is ₹ 2240