Question

the area of a rectangular field is x^3 + 3x^2 + 10x + 30 square units .find the perimeter of the field
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Answer 1

${x}^{3} + 3 {x}^{2} + 10x + 30 \\ = {x}^{2} (x + 3) + 10(x + 3) \\ = (x + 3)( {x}^{2} + 10) \\ = > l = {x}^{2} + 10 \: \: and \: \: b = x + 3 \\ p = l + b = ({x}^{2} + 10) + (x + 3) \\ = > p = {x}^{2} + x + 13$

Answer 2

Answer:

Step-by-step explanation:

2x^2+2x+26