the area of a rectangular field of breadth 48 m is the same as the area of square field of side 60 m. find the perimeter of the rectangular field
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=> Area of SQUARE = Area of RECTANGLE
=> AREA of SQUARE = Side × side
=> 60 × 60
=>![\large{\green{\boxed{\green{\boxed{\red{\textsf{3600sq.m }}}}}}} \large{\green{\boxed{\green{\boxed{\red{\textsf{3600sq.m }}}}}}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Cgreen%7B%5Cboxed%7B%5Cgreen%7B%5Cboxed%7B%5Cred%7B%5Ctextsf%7B3600sq.m+%7D%7D%7D%7D%7D%7D%7D)
=> Area of RECTANGLE = L × B
=> 3600 = L × 48
=> L = 3600/48
=>![\large{\green{\boxed{\green{\boxed{\red{\textsf{L = 75m }}}}}}} \large{\green{\boxed{\green{\boxed{\red{\textsf{L = 75m }}}}}}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Cgreen%7B%5Cboxed%7B%5Cgreen%7B%5Cboxed%7B%5Cred%7B%5Ctextsf%7BL+%3D+75m+%7D%7D%7D%7D%7D%7D%7D)
=> PERIMETER of RECTANGLE = 2 ( L + B )
=> 2 ( 75 + 60 )
=> 150 + 120
=>![\large{\green{\boxed{\green{\boxed{\red{\textsf{270m }}}}}}} \large{\green{\boxed{\green{\boxed{\red{\textsf{270m }}}}}}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Cgreen%7B%5Cboxed%7B%5Cgreen%7B%5Cboxed%7B%5Cred%7B%5Ctextsf%7B270m+%7D%7D%7D%7D%7D%7D%7D)
Therefore the PERIMETER of RECTANGLE is 270 m
=> AREA of SQUARE = Side × side
=> 60 × 60
=>
=> Area of RECTANGLE = L × B
=> 3600 = L × 48
=> L = 3600/48
=>
=> PERIMETER of RECTANGLE = 2 ( L + B )
=> 2 ( 75 + 60 )
=> 150 + 120
=>
Therefore the PERIMETER of RECTANGLE is 270 m
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