The area of a rectangular field whose length is twice its breadth is 2450 m Find the perimeter of the field
Answers
Answered by
52
Let the breadth be x then length is 2x.
So, 2x^2=2450
x^2=1225
x=35 m
and perimeter=2(x+2x)=6x=210 m
So, 2x^2=2450
x^2=1225
x=35 m
and perimeter=2(x+2x)=6x=210 m
Answered by
73
Let the breadth of the field be x.
Therefore, length if the field will be 2x.
Area of field = 2450
or, x × 2x = 2450
or, 2x² = 2450
or, x² = 2450/2
or, x² = 1225
or, √x² = √1225
or, x = 35m
if Breadth = 35m
Then length = 35 × 2 m = 70m
Perimeter of field = 2(length+ breadth)
= 2 (35+70)
= 2 × 105
= 210m
Answer) Perimeter of field is 210m.
Therefore, length if the field will be 2x.
Area of field = 2450
or, x × 2x = 2450
or, 2x² = 2450
or, x² = 2450/2
or, x² = 1225
or, √x² = √1225
or, x = 35m
if Breadth = 35m
Then length = 35 × 2 m = 70m
Perimeter of field = 2(length+ breadth)
= 2 (35+70)
= 2 × 105
= 210m
Answer) Perimeter of field is 210m.
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