Question

The area of a rectangular field whose length is twice its breadth is 2450 m2. Find the

perimeter of the field​

Answer 1

$\huge\bold\pink{Answer}$

The area of a rectangular field whose length is twice its breadth is 2450 sq.m. Find the perimeter of the field

Let say Breadth = B m

then Length = 2B m

Area =Length * Breadth

2B * B

Breadth = 35 m

Length = 2 × 35 = 70 m

Perimeter = 2 × (Breadth + Length)

= 2 × (35 + 70)

= 2 × 105

= 210 m

Answer 2

Answer:

210 m

Explanation:

Let the breadth be a

The length is twice the breadth,which means that,

Length=2a

Area of a rectangle=length×breadth

=2a×a

=2a^2

2a^2=2450 sq.m

a^2=2450÷2

a^2=1225

a=35. [take sq.rt on both sides->√1225=35]

Therefore,

Breadth=35 m

Length=70 m

Perimeter=2(length+breadth)

=2(70+35)

=2×105

=210 m