The area of a rectangular field whose length is twice its breadth is 2450 m Find the perimeter of the field
Answers
Answered by
13
Let the breadth be x
so length = 2x
area of rectangle= length × breadth
2450=2x×x
2450=2x^2
x^2=1225
x=35 m
So breadth = 35 m
Length = 70 m
perimeter =2 (35+70)
=2×105
=210m
So perimeter of rectangleis 210 m
so length = 2x
area of rectangle= length × breadth
2450=2x×x
2450=2x^2
x^2=1225
x=35 m
So breadth = 35 m
Length = 70 m
perimeter =2 (35+70)
=2×105
=210m
So perimeter of rectangleis 210 m
Answered by
5
l=2b
l*b=2450
2b^2=2450
2b^2=2450
b^2=1225
b=35
l=2*35
l=70
perimeter=2(l+b)
=2(70+35)
2(105)
=210m
l*b=2450
2b^2=2450
2b^2=2450
b^2=1225
b=35
l=2*35
l=70
perimeter=2(l+b)
=2(70+35)
2(105)
=210m
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