Math, asked by tejashri55, 5 months ago


The area of a rectangular field whose length is twice its breadth is
2450 m2. Find the perimeter of the field

Answers

Answered by sukirtha313
4

Answer:

105 cm

Step-by-step explanation:

Breadth of field = b

Length of field = 2b

Area of field = 2b²

2b² = 2450

b² = 1225

b = √1225

b = 35 cm

Perimeter = 35 + 70 = 105 cm

Answered by Anonymous
21

Answer :-

Perimeter = 210 m.

Explanation :-

Given :

  • Area of Rectanglular Field = 2450 sq.m
  • Length is twice its breadth.

To Find :

  • Perimeter of Field.

Solution :

Let,

Breadth of Rectangle = x.

So, Length of Rectangle = 2x.

According to the Question,

➨ (2x)(x) = 2450 m²

➨ 2x² = 2450 m²

➨ x² = 2450/2.

➨ x² = 1225.

➨ x = 35m.

Therefore,

  • Breadth of Rectangle = x = 35 m.
  • Length of Rectangle = 2x = 70 m.

We have to find Perimeter.

So,

➨ Perimeter = 2(l + b).

➨ Perimeter = 2(35 + 70).

➨ Perimeter = 2(105).

➨ Perimeter = 210 m.

Therefore, Perimeter of Rectangle = 210 m.

Similar questions