Question

The area of a rectangular field whose length is
twice its breadth is 684.5 m². Find the perimeter of
the field.​

Answer 1

Answer:

area = l*b

let , l = 2b

684.5 = 2b*b

342.25 = b^2

b = √342.5

b= 18.50

l = 2*18.50

l= 37

perimeter of rectangle = 2(l+b)

2(37+18.5)=111 m