Question

The area of a rectangular field whose length is twice its breadth is 2450 m2. find the perimeter of the field

Answer 1

HERE'S YOUR ANSWER....✌️✌️

AREA =2450 m2

Let the breadth be b ,
so, length = 2b

B.T.P,

b × 2b = 2450

=> 2b^2 = 2450

=> b^2 = 1225

=> b = √ 1225

=> b = 35

So,
LENGTH = 2×35 = 70m
BREADTH = 35m

PERIMETER
= 2(l + b)
= 2(35+70)
= 210m

^_^

Answer 2

$\textbf{Answer}$

Suppose the breadth of a rectangular field is B m.

Since length is twice its breadth,
=> $\textbf{length = 2B m}$

We know that,
$\textbf{Area = length}$ × $\textbf{breadth}$

Since given area is 2450 m^2,
=> (B) × (2B) = 2450
=> 2 B^2 = 2450
=> B^2 = 2450/2
=> B^2 = 1225
=> B^2 = (35)^2
=> B = +35 or -35

Since breadth can not be a negative number,
=> $\textbf{B = 35 m}$

=> $\textbf{2B = 70 m}$

$\textbf{We know that,}$
$\textbf{Perimeter = 2(length + breadth)}$

=> Perimeter = 2(35+70)
=> $\textbf{Perimeter = 210 m}$

$\textbf{Hope My Answer Helped}$
$\textbf{Thanks}$