Math, asked by Sarvanikolagotla, 18 hours ago

The area of a rectangular field whose length is twice its breadth is 6050 m². The perimeter of the field is:

a. 155m
b. 330m
c. 370m
d. 430m​

Answers

Answered by ShiNely
19

Answer:

\sf\pink{Answer†↓}

Breadth is =>6050m²

=Let the Breadth of the field be (x metres)

Then length of the field is (2x metres)

Therefore, area of the rectangular field = B

=>2x × x

=>(2x)²

Given:-

That area is 6050m²

Therefore, 2x²=6050

 \sf  =  \geqslant \: {x}^{2} =     \frac{6050}{2}  \\ \sf{x =  \sqrt{3025} } \\  \sf{x = 55}

 \sf{breadth = 55 } \\  \sf{length = 55 \times 2 = 110m}

\sf\orange{perimeter \: of \: the \: field = 2(l + b)} \\ \sf\green{ = 2(110 + 55)m} \\  \sf\red{ = 2 \times 165 \: m} \\  \sf{=330m }

so, option (B) is correct

=330m

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