The area of a rectangular field whose length is twice its breadth is 2,450 metre square.Find the perimeter of the field.
Answers
Answered by
2
l=2b
l=x
b=2x
according to the que
l×b=area
x ×2x=2450m^2
2x^2=2450
x^2=1225
x=35m
l=35m
b=70m
2(l+b)=perimeter
2(35+70)
2(105)
p=210m
l=x
b=2x
according to the que
l×b=area
x ×2x=2450m^2
2x^2=2450
x^2=1225
x=35m
l=35m
b=70m
2(l+b)=perimeter
2(35+70)
2(105)
p=210m
Answered by
4
Question:-
The area of a rectangular field whose length is twice its breadth is 2,450 metre square.Find the perimeter of the field.
Solution:-
Let, L be the length of rectangle and B be
the breadth rectangle.
By Question:-
L = 2B ....... ( 2 )
we know formula
=> Area of rectangle = L × B
From ( 1 )
=> Area of rectangle = 2B × B
=> 2450 = 2B²
i.e.
=> 2B² = 2450
=> B² =2450/2
=> B² = 1225
=> B = √1225
=> B = 35 cm
Put value of B in equation ( 1 )
=> L = 2B = 2 × 35 = 70 cm
=> Perimeter of rectangle = 2(L+B)
=> Perimeter of rectangle = 2(70+35)
=> Perimeter of rectangle = 2(105)
=> Perimeter of rectangle = 210 m
Hence perimeter of rectangle
is 210 m.
i hope it helps you.
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