Math, asked by vbsenthilrajkumar, 10 months ago

The area of a rectangular floor of a room is 320 square metre how many square tiles of Side 2 cm are required to cover the floor?​

Answers

Answered by rowan69
1

Step-by-step explanation:

in this question we have the area of the floor which is 320m^2

area of single tile is 2*2 =4

so no of tiles is 320/4

now the answer will be 80

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Answered by Anonymous
3

\huge\bold\blue{Question}

The area of a rectangle floor of a room is 320 square metre how many square tiles of Side 2 cm are required to cover the floor?

\huge\bold\red{\underline{\underline{Answer:}}}

\bold{800000 \ tiles \ are \ required \ to \ cover \ the \ floor}

\huge\bold\blue{Explanation}

Area of tile × Number of tiles

=Area of rectangular floor

i.e.

Number of tiles=Area of rectangular floor÷Area of tile

\huge\bold\orange{Given:}

\bold{Area \ of \ rectangular \ floor=320m^{2}}

\bold{Side \ of \ square \ shaped \ tile=2cm}

\huge\bold\pink{To \ find:}

\bold{Number \ of \ tiles \ require \ to \ cover \ floor}

\huge\bold\green{\underline{\underline{Solution}}}

\bold{1m=100cm}

\bold{1cm=\frac{1m}{100}}

\bold{2cm=\frac{2m}{100}}

Hence,side of a squared shape tile=0.02m

\bold{Area \ of \ tile=}=0.0004\bold{m^{2}}

Number of tiles required=

Area of rectangular floor÷Area of tile

(Multiply numenator and denominator by 10000)

\bold{=\frac{3200000}{4}}

\bold{=800000}

\huge\bold\red{Verification}

\bold{Area \ of \ tile ×number \ of \ tiles}

=0.0004×800000

=\bold{360m^{2}}

=\bold{Area \ of \ rectangular \ floor}

Therefore,

\bold\purple{800000 \ square \ tiles \ are \ required.}

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