The area of a rectangular frame is 96 sq. cm. If the sides are in the ratio 2 : 3, find the perimeter of the frame?
Answers
Answer:
Let length be 3x and breadth be 2x. Then
Area of frame = length x breadth
⇒864=3x×2x
⇒x
2
=144⇒x=
144
=12 cm
Therefore, length =3×12=36 cm
THE CORRECT ANSWER IS 40 cm.
GIVEN -
area of rectangular frame - 96 sq.cm
Sides in the ratio - 2:3
To find - perimeter of the frame
solution-
Step -1 - the ratio of the sides is given to us as 2:3
So, taking it as breadth - 2x and
length - 3x for better understanding
Step 2- putting the values of the sides in the area formula of a rectangle shape frame .
Formula of area of rectangle - L×B
So, accordingly
= 2x × 3x = 96 sq . Cm
= 6x^2 = 96 sq. Cm
Value of x^2
X^2 = 96/6
X^2 = 16 cm
X= √16 cm
X= 4 cm
Step 3 - So value of x =4 cm .
Now inserting the value of x in the ratio of sides in order to get length and breadth of a rectangle
2x=2× 4=8 cm
3x =3× 4= 12 cm
Length = 12 cm
Breadth = 8 cm
Step 4- finding perimeter of the rectangular frame
Formula- 2(l+b)
= 2(12+8)
=2(20)
=40 cm
So, the perimeter of the rectangular frame is 40 cm .
Hence , the answer of the question is 40 cm.
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