Question

The area of a rectangular garden is 4800 m and its breadth is 48 m. It has a road I m wide around the garden externally. This road is to be covered by bricks. If the expenditure per square metre is Rs 5, find the total cost for covering the road with bricks.​

Answer 1

ANSWER : ₹1500

Area of Rectangular Garden = 4800 m^2

We, know that Breadth = 48 m

So, we can find length by -

$l \times b \\ 48m \times l = 4800 {m}^{2} \\ l = \frac{4800 {m}^{2} }{48m} \\ l = 100m$

We know that there is a road 1m wide around ( outside ) the garden.

So, Length of Garden with Road= 100 + 1 + 1= 102m

Breadth of Garden with Road= 48 + 1 + 1= 50m

$area = l \times b \\ = 102m \times 50m \\ = 5100 {m}^{2}$

So, we need to cover this road by bricks. Hence, we need to find the area of road which is

Area of Garden with Road - Area of Garden

$5100 {m}^{2} - 4800 {m}^{2} \\ = 300 {m}^{2}$

We know the cost of covering bricks per m^2 = ₹5

So, Cost of Covering 300 m^2 ( Area of Road )

$300 \times 5 \\ = Rs \: 1500$

⭐Hope it Helps⭐