Question

The area of a rectangular garden is 4a2-64 square units. If one side is 2a-8 What is the other side?

Answer 1

Answer:

Other side will be 2a+8

Step-by-step explanation:

let one side be 'L' and other side be 'B'

Area of rectangle = L × B

Area = 4a²-64

L × B = 4a²-64

2a-8 × B = 4a²-64

B = (2a-8)(2a+8)/2a-8

By applying (a-b) (a+b) = a²-b²

B = 2a+8

Answer 2

Answer:

The area of regtangle =

$l \times b$

here ,

$l = 2a - 8$

and area of regtangle is

$4a {}^{2} - 64$

Thus ,

$(2a - 8) \times b = 4 {a}^{2} - 64 \\ \\ b = \frac{ 4 {a}^{2} - 64}{2a - 8} \\ \\ b = \frac{ (2a + 8)(2a - 8) }{2a - 8} \\ \\ b = 2a + 8$

Therefore, The answer is 2a+8