Question

The area of a rectangular garden of length 40 and is 1000 sqm. Find the breadth of the garden and its perimeter pointe the garden is to be NCL oecd by three round of NCR ING leaving as and intent of 4 m find the cost of frequency the garden at a rate of 2050 rupees per metre

Answer 1

length =40
area=1000 sq
breadth=1000/40
breadth=25
and perimeter is =2(25+40)
perimeter= 130
I do not understand this question in last

Answer 2

area =l* b
1000= 40*b
25 = b
perimeter = 2(l+b)
2(40+25)
130
total fencing = 130 - 12= 118
cost of fencing = 118*2050
= 241900
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