Math, asked by ishankhuperkar, 14 hours ago

The area of a rectangular garden of length 40 m ,is 1000sqm. Find the breadth of the garden and it's perimeter. The garden is to be enclosed by 3 rounds of fencing leaving an entrance of 4m. Find the cost of fencing the garden at a rate of 250 ruppes per meter.​

Answers

Answered by Anonymous
0

Answer:

Area =L×B

L×B=1000m

2

40m×B=1000m

2

B=

40m

1000m

2

B=25m

perimeter =2(L+B)

=2(40+25)

=2×65m=130m

Entrance 4m so 130m−4m=126m

Fencing 3 rounds so ÷3×perimeter

=3×126=378m

Given cost of fencing 250 Rs per 1m

So ⇒378×250

=94500 rupees.

Answered by vanshika3920
0

Answer:

Hope it helps

Mark it as brainlest

Attachments:
Similar questions