Question

the area of a rectangular garden of length 40m, is 1000 sqm. Find the breadth of the garden and it's perimeter . The garden is be enclosed by 3 rounds of fencing , leaving an entrance of 4m. Find the cost of fencing the garden at a rate of 250 rupees per metre .​

Answer 1

Answer:

RS.88500

Step-by-step explanation:

GIVEN:

LENGTH=40M

AREA=1000sqm

therefore,BREADTH=AREA/LENGTH

=1000/40 =25m

NOW,it's PERIMETER=2(L+B)

                                   =2( 40+25)

                                   =2 x 65

                                    =130

NOW,GARDEN HAS TO BE FENCED ,LEAVING AN ENTRANCE

SO, PERIMETER TO BE FENCED =(130 -(4 x 3) x 3)    [because we have to enclose by 3 rounds of fencing,and leave a entrance of 4m}

                                                      =(118 x 3)m

                                                       =354m

 AND ,NOW COST OF FENCING =RS 250 per m

therefore,=RS.(250 x 354)

                 =RS.88500 ANS.      

Answer 2

Question:-

The area of a rectangular garden of length 40 m, is 1000 sqm. Find the breadth of the garden and its perimeter The garden is to be enclosed by 3 rounds of fencing, leaving an entrance of 4m. Find the cost of fencing the garden at a rate of 250 rupees per metre.

To Find:-

• Find the breadth of the garden and its perimeter.

• The cost of fencing of the garden.

Solution:-

Let the breadth of the garden be ‘ x ’

First ,

We have to find the breadth:-

$\sf\longrightarrow \: Area = length \times breadth$

$\sf\longrightarrow \: 1000 = 40 \times x$

$\sf\longrightarrow \: 1000 = 40x$

$\sf\longrightarrow \: x = \cancel\dfrac { 1000 } { 40 }$

$\sf\pink\longrightarrow \: x = 25$

Now ,

We have to find the perimeter:-

$\sf\longrightarrow \: Perimeter = 2( l + b )$

$\sf\longrightarrow \: Perimeter = 2( 40 + 25 )$

$\sf\longrightarrow \: Perimeter = 2( 65 )$

$\sf\longrightarrow \: Perimeter = 130$

Now ,

We have to find the length of fencing:-

$\sf\longrightarrow\red \: Length ~for~ fencing = 3( 130 - 4 )$

$\sf\longrightarrow \: Length~ for ~fencing = 3( 126 )$

$\sf\longrightarrow \: Length~ for ~fencing = 378 m$

Now ,

We have to find the cost of fencing:-

$\sf\longrightarrow \: Cost \: of \: meter = 250 ₹$

$\sf\longrightarrow \: Cost \: of \: 378 \: m = 250 \times 378$

$\sf\longrightarrow \: Cost = ₹ 94500$

Hence ,

Cost is 94500