The area of a rectangular garden of length 40m, is 1000 sqm. Find the breadth of the garden and its perimeter. The garden is to be enclosed by 3 rounds of fencing, leaving an entrance of 4 m. Find the cost of fencing the garden at a rate of 250 rupees per metre.
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Answered by
32
is the ans ... b =25 perimeter =58 and cost=13500
sam583:
which will be area/lenght ... 1000÷40=25
then find perimeter i.e 2 (l+b) =2 (25+40)=130m
then as given u have to leave space i.e.4 m
so 130-4
then as given that there should be 3 rounds so 126×3=378
then to find total cost 378×250=94500
fine
?????
Thx sir so much .....
I have exam tomorrow and you helped me
Answered by
19
Answer:
1) Breadth = 25 m and Perimeter= 130 m
2) Cost=94500 rupees
Step-by-step explanation:
Given : The area of a rectangular garden of length 40m, is 1000 sqm.
The garden is to be enclosed by 3 rounds of fencing, leaving an entrance of 4 m.
To find :
1) The breadth of the garden and its perimeter.
2) The cost of fencing the garden at a rate of 250 rupees per metre.
Solution :
1) We have given,
Area=A=1000 m²
length=l=40m
breadth=b=?
A=l×b
1000/40=b
25=b
Breadth =25m
Perimeter of the garden,
P=2(l+b)
P=2(40+25)
P=2×65
Perimeter =130 m
2) Total fence is required to fence 3 times rectangular garden is
=130×3
=390 m
Now, leaving an entrance total 4m×3=12m
Required fence is =390-12 =378m
The cost of total fence is
C=378×250
C=94500 rupees
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